(2p-3q)(p^2-3pq+2q^2)=0

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Solution for (2p-3q)(p^2-3pq+2q^2)=0 equation: 


Simplifying
(2p + -3q)(p2 + -3pq + 2q2) = 0

Reorder the terms:
(2p + -3q)(-3pq + p2 + 2q2) = 0

Multiply (2p + -3q) * (-3pq + p2 + 2q2)
(2p * (-3pq + p2 + 2q2) + -3q * (-3pq + p2 + 2q2)) = 0
((-3pq * 2p + p2 * 2p + 2q2 * 2p) + -3q * (-3pq + p2 + 2q2)) = 0

Reorder the terms:
((4pq2 + -6p2q + 2p3) + -3q * (-3pq + p2 + 2q2)) = 0
((4pq2 + -6p2q + 2p3) + -3q * (-3pq + p2 + 2q2)) = 0
(4pq2 + -6p2q + 2p3 + (-3pq * -3q + p2 * -3q + 2q2 * -3q)) = 0
(4pq2 + -6p2q + 2p3 + (9pq2 + -3p2q + -6q3)) = 0

Reorder the terms:
(4pq2 + 9pq2 + -6p2q + -3p2q + 2p3 + -6q3) = 0

Combine like terms: 4pq2 + 9pq2 = 13pq2
(13pq2 + -6p2q + -3p2q + 2p3 + -6q3) = 0

Combine like terms: -6p2q + -3p2q = -9p2q
(13pq2 + -9p2q + 2p3 + -6q3) = 0

Solving
13pq2 + -9p2q + 2p3 + -6q3 = 0

Solving for variable 'p'.

The solution to this equation could not be determined.

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